Thermodynamics of Electrochemical Cells
Thermodynamics of Electrochemical Cells
If in a cell n
equivalents of reactants are converted into products, then the quantity of
electricity that flows through the cell is nF, where F is the Faraday constant.
If this amount of charge is transported through the cell of Emf E volts, the
amount of electrical work done by the cell is nEF.
Gibbs free
energy decrease in a cell reaction is therefore given by;
-G=nEF
or G=-nEF (18)
If at constant
temperature and pressure (G)P,T< 0 or Ecell> 0, the
cell reaction can proceed spontaneously. However, if(G)P,T =0 Ecell=
0, the cell is in a state of equilibrium..
or
Eqn (18)
provides a method for determining free energy changes of electrochemical cell
reactions.
The enthalpy
change for a cell reaction may also be deduced from Emf measurements. From
Gibbs-Helmoholtz equation we have;
H =-G –T []P (19)
Differentiating
G with respect to temperature at constant pressure in eqn (18) yields;
[(G/T]P
= -nF P (20)
The quantity P is the temperature coefficient of the cell.
Substituting the value of [(G/T]P in eqn (2) we get;
H= G + nFT P
And substituting
for ΔG from eqn (1) gives;
H=nFE + nFT P
Thus from a
measurement of the cell Emf and the rate of change of Emf with temperature, the
enthalpy change, H, may be calculated.
Entropy changes
for cell reactions are determined from temperature coefficient of the cell Emf.
From the third
law of thermodynamics we have
G =H –TS (21)
Differentiating
G with respect to temperature at constant pressure we get
[(G/T]P
= -S
(22)
Substituting the value of [(G/T]P
from equation (20) gives
-nFP = S
or
S = nFP
(23)
Eqn (23) above
can be used for calculating entropy changes from the temperature coefficient of
the cell.
Although
electrochemical methods of determining the thermodynamics quantities G, H and S
are most attractive in theory, in practice it is difficult to obtain accurate
results unless immense precautions are taken during the experiment. The values
obtained can only be regarded as approximate.
Exercise 5
Given the
following electrochemical cell
Pb/PbCl2/HCl
(1M)/AgCI/Ag
The Emf of the
cell at 298K is 0.490V. If the rate of change of the Emf with temperature is
1.86 x 10-4 volt/degree, calculate G, H and S for the cell reaction.
WterfdiaZcile German Cirulis https://wakelet.com/wake/OVk7xlWKqiQNHfJOIW_Sm
ReplyDeletenabseiteti
UrapceaYsau-go Nikki Marie click here
ReplyDeletedownload
click here
download
clinlatabmarg