Application of EMF Measurements
Application of EMF Measurements
i) Determination of
Equilibrium Constant
Measurement of
the standard Emf of the cell, E°Cell, enables one to evaluate the
equilibrium constant for the electrode reaction.
The relation
between the standard free energy change and the equilibrium constant of a
reaction is given by:
G0=
-RT In K
But the standard
free energy is related to the standard electrode potential by the expression:
G0 =
-nE0F
Hence
E0 =
In K
At 298K
E0 =
log K
Exercise 4
For the
following electrochemical cell
Zn/Zn2+//Fe3+,Fe2+/Pt
Whose standard
Emf is 1 .534V, the overall cell reaction is
Fe3 + +
1/2Zn Fe2+ +1/2 Zn2+
ii) Determination of Solubility Products
This is a useful
technique to evaluate the solubility product of sparingly soluble salt such as
AgCI. The saturated solution of AgCl in water is so dilute that it is
completely ionized as:
AgCl(s)Ag+(aq)+Cl-(aq) (9)
The solubility
product is given by:
Ksp=aAg+
x aC1- (10)
For solutions of
high dilution and activity may be
replaced by concentration. Ksp for AgC1 may be determined from Emf
measurements by employing a suitable cell whose overall cell reaction will be
that given by eqn 9 above. A suitable cell would be
Ag(s)/Ag+(aq)//Cl-(aq)/AgCI(s)/Ag
Left electrode: Ag Ag+ + e E0=
-0.799V
Right electrode:
AgCI + e Ag + Cl-
E° = +0.2225V
Overall: AgCl Ag+ + Cl-
E°cell = -0.5765
The cell Emf is
given by:
E=E0 - — In aAg+x aCl-
E=E0 - — In Ksp
At equilibrium
the cell would not be able to perform any useful work and hence ECell =
0.
We also know
that
G0 =
-nE0F = -RT In Ksp
or
E0 =
In Ksp
At 298K
E°=0.0591 log Ksp
Log Ksp
=
Therefore Ksp
= 1.76 x 10-10 mol2 dm-6
The solubility
of AgCl may be evaluated from the solubility product. Since the concentration
of Ag+ equals that of C1, we may write
[Ag+]=
[Cl-] = (Ksp)1/2 = (1.76 x 10-10)1/2
Hence the
solubility of AgCl is 1.32 x 10-5 mol dm-3
iii) Determination of pH
One of the most
important applications of Emf measurements is the determination of the pH of
solution. In principle, the activity of hydrogen ions or the concentration of
hydrogen ions can be determined by setting a cell in which one of the
electrodes is reversible to hydrogen ions.
In practice the
hydrogen electrode is combined with another reference electrode such as
standard hydrogen electrode (SHE) or a saturated calomel electrode (SCE) or any
other reference electrode. ..
For the single
hydrogen electrode Pt/H2(1atm)/H+, the electrode reaction
is
1/2H2H++e
The electrode
potential is given by
E= In aH+ since E° H+/H2 = 0
By definition pH
= -log10aH+Hence the above equation becomes
E = + ()pH
At 298K
E=+0.0591pH (11)
Thus the Emf of
the cell is linearly dependent on the pH value of the solution. The hydrogen
electrode may be combined with a reference calomel electrode to obtain the
cell;
Pt/H2
(1atm)/H+(a1)//Cl-(a2)/Hg2Cl2/
Hg
As seen from
above the potential of the hydrogen electrode is given by:
EH2= In aH+
Since the calomel
electrode is a reference electrode its potential will be constant and hence its
potential may simply be referred to as reference potential written as E. The
Emf of the cell is given by;
Ecell=
ER – EL
= Eref – EH2
= Eref -0.0591 log aH+
=Eref + 0.0591 pH
pH = at 298K (12)
Thus by
measuring the Emf of a cell such as the one given above which has a reference
electrode of known potential, the pH of the solution can be determined.
iv) Determination of Activity Coefficients
Consider
a cell where a silver-silver chloride electrode is combined with a hydrogen
electrode to give the following cell:
Pt/H2(1atm)/HCl(m)/AgCl/Ag
The
overall cell reaction of the above cell is
1/2H2(g)
+ AgCl(s) Ag(s) + H+(aq) + Cl-(aq)
The
Emf of the cell is:
E
=ER –EL =E0Ag/AgCl – E0H+/H2
- (13)
By definition E0H+/H2=0,
and aAgCl =1
Also (PH2)1/2=
1 since PH2 =1 atm
Hence
E=E°Ag/AgCl
- In aH+aCl- (14)
The mean
activity a± of HCl is defined as:
a±2
=aH+aCl-
and
a± =m+
where ± is the
mean activity coefficient
E=E°Ag/AgCl
- In m- In± (15)
Directly
measurable quantities are rearranged on the left to give:
E + In m= E°Ag/AgCl
- In±
(16)
At298K
E+0.1181og m=E°Ag/AgCl
- 0.1181og± (17)
By measuring the
Emf of the cell at different molalities of hydrochloric acid, the quantity
(E+0.1181og m ) can be calculated at various molalities. If we plot(E+0.1181og
m ) against m and extrapolate to zero m,
we determine the value of E° because at
zero m± is unity so ln± = 0. Once we know the value
of E°, the mean activity coefficient can
be found at a particular value of m.
Thank u
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